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IBM C9050-042 Exam Syllabus Topics:

IBM Developing with IBM Enterprise PL/I Sample Questions:

1. Given the following code, which condition would be raised first (if ENABLED)?
DCL A(50000) CHAR (8);
DCL I BIN FIXED (31);
DCL J BINFIXED (15);
DCI = 1 TO 100_000;
J = I;
A(J) = I;
END;

A) SIZE
B) CONVERSION
C) SUBSCRIPTRANGE
D) FIXEDOVERFLOW

2. What characterizes the hierarchical data model with respect to data access?

A) Data access can only be sequential.
B) Data access supports parent-child relationships.
C) Data access supports tables.
D) Data access can only be via an index.

3. Which of the following statements is best for avoiding synchronously updating a resource?

A) Have only program A update the resource without using ENQ.
B) Have several programs update the resource without using ENQ.
C) Have all programs use ENQ and WAIT for a specific resource.
D) Lock the entire resource at start of program and release at end of program.

4. Given the following code, which procedure call would cause the "Pointer corrupted!" message to be output
provided that the PL/I compile time option CHECK(STORAGE) has been specified?
DCLX FIXED BIN(31) BASED (P);
DCL Y CHAR (5) BASED (P);
DCL P POINTER;
SUB: PROCEDURE (P);
DCL P POINTER;
if CHECKSTG(P) THEN PUT ('Pointer 0k!');
ELSE PUT ('Pointer corrupted!');
END;

A) ALLOCATEY;
Y = 'ABCDE';
CALL SUB (P);
B) ALLOCATEX;
Y = 'ABCD';
CALL SUB (P);
C) P = ALLOCATE (100);
Y = 'ABCDE';
CALL SUB (ADDR(X));
D) ALLOCATEY;
Y = 'ABCDE';
CALL SUB (ADDR(X));

5. Prerequisite:
A sorted input dataset with record length 100 contains at least one record for all the values '1', '2', '3' in
the first byte. The applied sort criteria is 1,100,ch,a.
Requirements:
1 .) All records with '1' in the first byte must be ignored.
2 .) All records with '2' in the first byte must be written to the output dataset.
3 .) If there is a '3' in the first byte, the program must not read more records.
4 .) The program must not abend or loop infinitely.
If the following code does not fulfill the requirements above, which would be the reason, if any?
DCL DDIN FILE RECORD INPUT;
DCL DDOUT FILE RECORD OUTPUT;
DCL 1 INSTRUC,
3 A CHAR(1),
3 * CHAR(99);
DCL EOF_IN BIT(1) INIT('0'B);
DCL (Z1,Z2,Z3,ZO) BIN FIXED(31) INIT(0);
ON ENDFILE(DDIN) EOF IN = '1'B;
READ FILE(DDIN) INTO (INSTRUC);
IF EOF_IN THEN LEAVE;
SELECT(INSTRUC .A);
WHEN('1') DO;
Z1 += Z1;
ITERATE LAB;
END;
WHEN('3') DO;
Z3 = Z3 + 1;
LEAVE;
END;
WHEN('2') DO;
Z2 = Z2 + 1;
WRITE FILE(DDOUT) FROM(INSTRUC);
END;
OTHER DO;
ZO = ZO + 1;
PUT SKIP LIST(INSTRUC.A);
END; END;/*SELECT*/
END;/*LOOP*/

A) The code does not fulfill the requirement, because the program will loop infinitely.
B) The code does not fulfill the requirement, because the READ iteration will not be left when the first
record with '3' in the first byte appears.
C) The code fulfills the requirement.
D) The code does not fulfill the requirement, because not all records with '2' in the first byte will be written
to the output dataset.

Solutions: